3(x+2)+6=2(x+4)-2

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Solution for 3(x+2)+6=2(x+4)-2 equation: 



3(x+2)+6=2(x+4)-2

We move all terms to the left:

3(x+2)+6-(2(x+4)-2)=0

We multiply parentheses

3x-(2(x+4)-2)+6+6=0



We calculate terms in parentheses: -(2(x+4)-2), so:

2(x+4)-2

We multiply parentheses

2x+8-2

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

3x-(2x+6)+12=0

We get rid of parentheses

3x-2x-6+12=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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