6+(x+4)=2+(3x+4)

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Solution for 6+(x+4)=2+(3x+4) equation: 



6+(x+4)=2+(3x+4)

We move all terms to the left:

6+(x+4)-(2+(3x+4))=0

We get rid of parentheses

x-(2+(3x+4))+4+6=0



We calculate terms in parentheses: -(2+(3x+4)), so:

2+(3x+4)

determiningTheFunctionDomain
(3x+4)+2

We get rid of parentheses

3x+4+2

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

x-(3x+6)+10=0

We get rid of parentheses

x-3x-6+10=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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