-2(x-4)+3=3(x+2)-5

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Solution for -2(x-4)+3=3(x+2)-5 equation: 



-2(x-4)+3=3(x+2)-5

We move all terms to the left:

-2(x-4)+3-(3(x+2)-5)=0

We multiply parentheses

-2x-(3(x+2)-5)+8+3=0



We calculate terms in parentheses: -(3(x+2)-5), so:

3(x+2)-5

We multiply parentheses

3x+6-5

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

-2x-(3x+1)+11=0

We get rid of parentheses

-2x-3x-1+11=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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