3(x+12)=-4x(3x-8)

Solution for 3(x+12)=-4x(3x-8) equation:

3(x+12)=-4x(3x-8)

We move all terms to the left:

3(x+12)-(-4x(3x-8))=0

We multiply parentheses

3x-(-4x(3x-8))+36=0


We calculate terms in parentheses: -(-4x(3x-8)), so:

-4x(3x-8)

We multiply parentheses

-12x^2+32x

Back to the equation:

-(-12x^2+32x)


We get rid of parentheses

12x^2-32x+3x+36=0

We add all the numbers together, and all the variables

12x^2-29x+36=0

a = 12; b = -29; c = +36;
Δ = b2-4ac
Δ = -292-4·12·36
Δ = -887
Delta is less than zero, so there is no solution for the equation