128=8(8+2b)

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Solution for 128=8(8+2b) equation: 



128=8(8+2b)

We move all terms to the left:

128-(8(8+2b))=0

We add all the numbers together, and all the variables

-(8(2b+8))+128=0



We calculate terms in parentheses: -(8(2b+8)), so:

8(2b+8)

We multiply parentheses

16b+64

Back to the equation:

-(16b+64)



We get rid of parentheses

-16b-64+128=0

We add all the numbers together, and all the variables

-16b+64=0

We move all terms containing b to the left, all other terms to the right

-16b=-64

b=-64/-16

b=+4

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