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3(x-4)=2-5(x+2)
We move all terms to the left:
3(x-4)-(2-5(x+2))=0
We multiply parentheses
3x-(2-5(x+2))-12=0
We calculate terms in parentheses: -(2-5(x+2)), so:We get rid of parentheses
2-5(x+2)
determiningTheFunctionDomain -5(x+2)+2
We multiply parentheses
-5x-10+2
We add all the numbers together, and all the variables
-5x-8
Back to the equation:
-(-5x-8)
3x+5x+8-12=0
We add all the numbers together, and all the variables
8x-4=0
We move all terms containing x to the left, all other terms to the right
8x=4
x=4/8
x=1/2
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