3(x+1)=6(x+2)

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Solution for 3(x+1)=6(x+2) equation:



3(x+1)=6(x+2)
We move all terms to the left:
3(x+1)-(6(x+2))=0
We multiply parentheses
3x-(6(x+2))+3=0
We calculate terms in parentheses: -(6(x+2)), so:
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
We get rid of parentheses
3x-6x-12+3=0
We add all the numbers together, and all the variables
-3x-9=0
We move all terms containing x to the left, all other terms to the right
-3x=9
x=9/-3
x=-3

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