(2-y)-y=2(y+1)

Solution for (2-y)-y=2(y+1) equation:

(2-y)-y=2(y+1)

We move all terms to the left:

(2-y)-y-(2(y+1))=0

We add all the numbers together, and all the variables

(-1y+2)-y-(2(y+1))=0

We add all the numbers together, and all the variables

-1y+(-1y+2)-(2(y+1))=0

We get rid of parentheses

-1y-1y-(2(y+1))+2=0


We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)


We add all the numbers together, and all the variables

-2y-(2y+2)+2=0

We get rid of parentheses

-2y-2y-2+2=0

We add all the numbers together, and all the variables

-4y=0

y=0/-4

y=0