3(x+1)=-6(2x+3)-8x

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Solution for 3(x+1)=-6(2x+3)-8x equation: 



3(x+1)=-6(2x+3)-8x

We move all terms to the left:

3(x+1)-(-6(2x+3)-8x)=0

We multiply parentheses

3x-(-6(2x+3)-8x)+3=0



We calculate terms in parentheses: -(-6(2x+3)-8x), so:

-6(2x+3)-8x

We add all the numbers together, and all the variables

-8x-6(2x+3)

We multiply parentheses

-8x-12x-18

We add all the numbers together, and all the variables

-20x-18

Back to the equation:

-(-20x-18)



We get rid of parentheses

3x+20x+18+3=0

We add all the numbers together, and all the variables

23x+21=0

We move all terms containing x to the left, all other terms to the right

23x=-21

x=-21/23

x=-21/23

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