(14x-28)+5x=7(-28x-14)-3

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Solution for (14x-28)+5x=7(-28x-14)-3 equation: 



(14x-28)+5x=7(-28x-14)-3

We move all terms to the left:

(14x-28)+5x-(7(-28x-14)-3)=0

We add all the numbers together, and all the variables

5x+(14x-28)-(7(-28x-14)-3)=0

We get rid of parentheses

5x+14x-(7(-28x-14)-3)-28=0



We calculate terms in parentheses: -(7(-28x-14)-3), so:

7(-28x-14)-3

We multiply parentheses

-196x-98-3

We add all the numbers together, and all the variables

-196x-101

Back to the equation:

-(-196x-101)



We add all the numbers together, and all the variables

19x-(-196x-101)-28=0

We get rid of parentheses

19x+196x+101-28=0

We add all the numbers together, and all the variables

215x+73=0

We move all terms containing x to the left, all other terms to the right

215x=-73

x=-73/215

x=-73/215

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