3(x+1)=6(2x+3)-8x

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Solution for 3(x+1)=6(2x+3)-8x equation: 



3(x+1)=6(2x+3)-8x

We move all terms to the left:

3(x+1)-(6(2x+3)-8x)=0

We multiply parentheses

3x-(6(2x+3)-8x)+3=0



We calculate terms in parentheses: -(6(2x+3)-8x), so:

6(2x+3)-8x

We add all the numbers together, and all the variables

-8x+6(2x+3)

We multiply parentheses

-8x+12x+18

We add all the numbers together, and all the variables

4x+18

Back to the equation:

-(4x+18)



We get rid of parentheses

3x-4x-18+3=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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