3(x+1)/4-x=2(x+1)-(x+1)/2

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Solution for 3(x+1)/4-x=2(x+1)-(x+1)/2 equation: 



3(x+1)/4-x=2(x+1)-(x+1)/2

We move all terms to the left:

3(x+1)/4-x-(2(x+1)-(x+1)/2)=0

We add all the numbers together, and all the variables

-1x+3(x+1)/4-(2(x+1)-(x+1)/2)=0

We calculate fractions


-1x+3x/()+(-(2(x+1)-(x+1)*4)/()=0



We calculate terms in parentheses: +(-(2(x+1)-(x+1)*4)/(), so:

-(2(x+1)-(x+1)*4)/(

We multiply all the terms by the denominator


-(2(x+1)-(x+1)*4)



We calculate terms in parentheses: -(2(x+1)-(x+1)*4), so:

2(x+1)-(x+1)*4

We multiply parentheses

2x-4x+2-4

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We get rid of parentheses

2x+2

Back to the equation:

+(2x+2)



We get rid of parentheses

-1x+3x/()+2x+2=0

We multiply all the terms by the denominator


-1x*()+3x+2x*()+2*()=0

We add all the numbers together, and all the variables

3x-1x*()+2x*()=0

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