k-2k=-2(1+k)+4(-k-2)

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Solution for k-2k=-2(1+k)+4(-k-2) equation: 



k-2k=-2(1+k)+4(-k-2)

We move all terms to the left:

k-2k-(-2(1+k)+4(-k-2))=0

We add all the numbers together, and all the variables

k-2k-(-2(k+1)+4(-1k-2))=0

We add all the numbers together, and all the variables

-1k-(-2(k+1)+4(-1k-2))=0



We calculate terms in parentheses: -(-2(k+1)+4(-1k-2)), so:

-2(k+1)+4(-1k-2)

We multiply parentheses

-2k-4k-2-8

We add all the numbers together, and all the variables

-6k-10

Back to the equation:

-(-6k-10)



We get rid of parentheses

-1k+6k+10=0

We add all the numbers together, and all the variables

5k+10=0

We move all terms containing k to the left, all other terms to the right

5k=-10

k=-10/5

k=-2

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