4(7b+5)=19+3b

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Solution for 4(7b+5)=19+3b equation: 



4(7b+5)=19+3b

We move all terms to the left:

4(7b+5)-(19+3b)=0

We add all the numbers together, and all the variables

4(7b+5)-(3b+19)=0

We multiply parentheses

28b-(3b+19)+20=0

We get rid of parentheses

28b-3b-19+20=0

We add all the numbers together, and all the variables

25b+1=0

We move all terms containing b to the left, all other terms to the right

25b=-1

b=-1/25

b=-1/25

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