3(w0-5)=(2w+10)

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Solution for 3(w0-5)=(2w+10) equation: 



3(w0-5)=(2w+10)

We move all terms to the left:

3(w0-5)-((2w+10))=0

We add all the numbers together, and all the variables

3(w-5)-((2w+10))=0

We multiply parentheses

3w-((2w+10))-15=0



We calculate terms in parentheses: -((2w+10)), so:

(2w+10)

We get rid of parentheses

2w+10

Back to the equation:

-(2w+10)



We get rid of parentheses

3w-2w-10-15=0

We add all the numbers together, and all the variables

w-25=0

We move all terms containing w to the left, all other terms to the right

w=25

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