42=3(3-b)

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Solution for 42=3(3-b) equation:



42=3(3-b)
We move all terms to the left:
42-(3(3-b))=0
We add all the numbers together, and all the variables
-(3(-1b+3))+42=0
We calculate terms in parentheses: -(3(-1b+3)), so:
3(-1b+3)
We multiply parentheses
-3b+9
Back to the equation:
-(-3b+9)
We get rid of parentheses
3b-9+42=0
We add all the numbers together, and all the variables
3b+33=0
We move all terms containing b to the left, all other terms to the right
3b=-33
b=-33/3
b=-11

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