3(v-5)=2(v+15)

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Solution for 3(v-5)=2(v+15) equation: 



3(v-5)=2(v+15)

We move all terms to the left:

3(v-5)-(2(v+15))=0

We multiply parentheses

3v-(2(v+15))-15=0



We calculate terms in parentheses: -(2(v+15)), so:

2(v+15)

We multiply parentheses

2v+30

Back to the equation:

-(2v+30)



We get rid of parentheses

3v-2v-30-15=0

We add all the numbers together, and all the variables

v-45=0

We move all terms containing v to the left, all other terms to the right

v=45

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