(x-10)/3=(2x-80)/2

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Solution for (x-10)/3=(2x-80)/2 equation: 



(x-10)/3=(2x-80)/2

We move all terms to the left:

(x-10)/3-((2x-80)/2)=0

We calculate fractions


x/()+(-((2x-80)*3)/()=0



We calculate terms in parentheses: +(-((2x-80)*3)/(), so:

-((2x-80)*3)/(

We multiply all the terms by the denominator


-((2x-80)*3)



We calculate terms in parentheses: -((2x-80)*3), so:

(2x-80)*3

We multiply parentheses

6x-240

Back to the equation:

-(6x-240)



We get rid of parentheses

-6x+240

Back to the equation:

+(-6x+240)



We get rid of parentheses

x/()-6x+240=0

We multiply all the terms by the denominator


x-6x*()+240*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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