3y-3+4y=6y+12

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Solution for 3y-3+4y=6y+12 equation: 



3y-3+4y=6y+12

We move all terms to the left:

3y-3+4y-(6y+12)=0

We add all the numbers together, and all the variables

7y-(6y+12)-3=0

We get rid of parentheses

7y-6y-12-3=0

We add all the numbers together, and all the variables

y-15=0

We move all terms containing y to the left, all other terms to the right

y=15

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