3(v-2)-5=-5(-5v+1)-6v

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Solution for 3(v-2)-5=-5(-5v+1)-6v equation: 



3(v-2)-5=-5(-5v+1)-6v

We move all terms to the left:

3(v-2)-5-(-5(-5v+1)-6v)=0

We multiply parentheses

3v-(-5(-5v+1)-6v)-6-5=0



We calculate terms in parentheses: -(-5(-5v+1)-6v), so:

-5(-5v+1)-6v

We add all the numbers together, and all the variables

-6v-5(-5v+1)

We multiply parentheses

-6v+25v-5

We add all the numbers together, and all the variables

19v-5

Back to the equation:

-(19v-5)



We add all the numbers together, and all the variables

3v-(19v-5)-11=0

We get rid of parentheses

3v-19v+5-11=0

We add all the numbers together, and all the variables

-16v-6=0

We move all terms containing v to the left, all other terms to the right

-16v=6

v=6/-16

v=-3/8

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