3(u+2)+2u=7(u-1)

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Solution for 3(u+2)+2u=7(u-1) equation: 



3(u+2)+2u=7(u-1)

We move all terms to the left:

3(u+2)+2u-(7(u-1))=0

We add all the numbers together, and all the variables

2u+3(u+2)-(7(u-1))=0

We multiply parentheses

2u+3u-(7(u-1))+6=0



We calculate terms in parentheses: -(7(u-1)), so:

7(u-1)

We multiply parentheses

7u-7

Back to the equation:

-(7u-7)



We add all the numbers together, and all the variables

5u-(7u-7)+6=0

We get rid of parentheses

5u-7u+7+6=0

We add all the numbers together, and all the variables

-2u+13=0

We move all terms containing u to the left, all other terms to the right

-2u=-13

u=-13/-2

u=6+1/2

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