4(r-7)+2=5(r+3)-22

Solution for 4(r-7)+2=5(r+3)-22 equation:

4(r-7)+2=5(r+3)-22

We move all terms to the left:

4(r-7)+2-(5(r+3)-22)=0

We multiply parentheses

4r-(5(r+3)-22)-28+2=0


We calculate terms in parentheses: -(5(r+3)-22), so:

5(r+3)-22

We multiply parentheses

5r+15-22

We add all the numbers together, and all the variables

5r-7

Back to the equation:

-(5r-7)


We add all the numbers together, and all the variables

4r-(5r-7)-26=0

We get rid of parentheses

4r-5r+7-26=0

We add all the numbers together, and all the variables

-1r-19=0

We move all terms containing r to the left, all other terms to the right

-r=19

r=19/-1

r=-19