7(3y-2)=-26

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Solution for 7(3y-2)=-26 equation: 



7(3y-2)=-26

We move all terms to the left:

7(3y-2)-(-26)=0

We add all the numbers together, and all the variables

7(3y-2)+26=0

We multiply parentheses

21y-14+26=0

We add all the numbers together, and all the variables

21y+12=0

We move all terms containing y to the left, all other terms to the right

21y=-12

y=-12/21

y=-4/7

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