3(t-7)=5(3-t)+2t+6

Solution for 3(t-7)=5(3-t)+2t+6 equation:

3(t-7)=5(3-t)+2t+6

We move all terms to the left:

3(t-7)-(5(3-t)+2t+6)=0

We add all the numbers together, and all the variables

3(t-7)-(5(-1t+3)+2t+6)=0

We multiply parentheses

3t-(5(-1t+3)+2t+6)-21=0


We calculate terms in parentheses: -(5(-1t+3)+2t+6), so:

5(-1t+3)+2t+6

We add all the numbers together, and all the variables

2t+5(-1t+3)+6

We multiply parentheses

2t-5t+15+6

We add all the numbers together, and all the variables

-3t+21

Back to the equation:

-(-3t+21)


We get rid of parentheses

3t+3t-21-21=0

We add all the numbers together, and all the variables

6t-42=0

We move all terms containing t to the left, all other terms to the right

6t=42

t=42/6

t=7