4(t-1)=8+t

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Solution for 4(t-1)=8+t equation:



4(t-1)=8+t
We move all terms to the left:
4(t-1)-(8+t)=0
We add all the numbers together, and all the variables
4(t-1)-(t+8)=0
We multiply parentheses
4t-(t+8)-4=0
We get rid of parentheses
4t-t-8-4=0
We add all the numbers together, and all the variables
3t-12=0
We move all terms containing t to the left, all other terms to the right
3t=12
t=12/3
t=4

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