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2400=3x*4x
We move all terms to the left:
2400-(3x*4x)=0
We add all the numbers together, and all the variables
-(+3x*4x)+2400=0
We get rid of parentheses
-3x*4x+2400=0
Wy multiply elements
-12x^2+2400=0
a = -12; b = 0; c = +2400;
Δ = b2-4ac
Δ = 02-4·(-12)·2400
Δ = 115200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{115200}=\sqrt{57600*2}=\sqrt{57600}*\sqrt{2}=240\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{2}}{2*-12}=\frac{0-240\sqrt{2}}{-24} =-\frac{240\sqrt{2}}{-24} =-\frac{10\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{2}}{2*-12}=\frac{0+240\sqrt{2}}{-24} =\frac{240\sqrt{2}}{-24} =\frac{10\sqrt{2}}{-1} $
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