3(t-18)=12(2-3t)

Solution for 3(t-18)=12(2-3t) equation:

3(t-18)=12(2-3t)

We move all terms to the left:

3(t-18)-(12(2-3t))=0

We add all the numbers together, and all the variables

3(t-18)-(12(-3t+2))=0

We multiply parentheses

3t-(12(-3t+2))-54=0


We calculate terms in parentheses: -(12(-3t+2)), so:

12(-3t+2)

We multiply parentheses

-36t+24

Back to the equation:

-(-36t+24)


We get rid of parentheses

3t+36t-24-54=0

We add all the numbers together, and all the variables

39t-78=0

We move all terms containing t to the left, all other terms to the right

39t=78

t=78/39

t=2