(5s+1)/2s=-1/3

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Solution for (5s+1)/2s=-1/3 equation: 



(5s+1)/2s=-1/3

We move all terms to the left:

(5s+1)/2s-(-1/3)=0



Domain of the equation: 2s!=0

s!=0/2

s!=0

s∈R



We get rid of parentheses

(5s+1)/2s+1/3=0

We calculate fractions


(15s+3)/6s+2s/6s=0

We multiply all the terms by the denominator


(15s+3)+2s=0

We add all the numbers together, and all the variables

2s+(15s+3)=0

We get rid of parentheses

2s+15s+3=0

We add all the numbers together, and all the variables

17s+3=0

We move all terms containing s to the left, all other terms to the right

17s=-3

s=-3/17

s=-3/17

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