b-5(1+2b)=-41-3b

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Solution for b-5(1+2b)=-41-3b equation: 



b-5(1+2b)=-41-3b

We move all terms to the left:

b-5(1+2b)-(-41-3b)=0

We add all the numbers together, and all the variables

b-5(2b+1)-(-3b-41)=0

We multiply parentheses

b-10b-(-3b-41)-5=0

We get rid of parentheses

b-10b+3b+41-5=0

We add all the numbers together, and all the variables

-6b+36=0

We move all terms containing b to the left, all other terms to the right

-6b=-36

b=-36/-6

b=+6

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