3(q-5)=4(2q+10)/2

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Solution for 3(q-5)=4(2q+10)/2 equation: 



3(q-5)=4(2q+10)/2

We move all terms to the left:

3(q-5)-(4(2q+10)/2)=0

We multiply parentheses

3q-(4(2q+10)/2)-15=0

We multiply all the terms by the denominator


3q*2)-(4(2q+10)-15*2)=0

We add all the numbers together, and all the variables

3q*2)-(4(2q+10)=0

Wy multiply elements

6q^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{0}{12}=0$

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