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4(2y+1)=2(y-14)
We move all terms to the left:
4(2y+1)-(2(y-14))=0
We multiply parentheses
8y-(2(y-14))+4=0
We calculate terms in parentheses: -(2(y-14)), so:We get rid of parentheses
2(y-14)
We multiply parentheses
2y-28
Back to the equation:
-(2y-28)
8y-2y+28+4=0
We add all the numbers together, and all the variables
6y+32=0
We move all terms containing y to the left, all other terms to the right
6y=-32
y=-32/6
y=-5+1/3
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