6(y+2)+3(2y-3)=39-2(y+4)

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Solution for 6(y+2)+3(2y-3)=39-2(y+4) equation: 



6(y+2)+3(2y-3)=39-2(y+4)

We move all terms to the left:

6(y+2)+3(2y-3)-(39-2(y+4))=0

We multiply parentheses

6y+6y-(39-2(y+4))+12-9=0



We calculate terms in parentheses: -(39-2(y+4)), so:

39-2(y+4)

determiningTheFunctionDomain
-2(y+4)+39

We multiply parentheses

-2y-8+39

We add all the numbers together, and all the variables

-2y+31

Back to the equation:

-(-2y+31)



We add all the numbers together, and all the variables

12y-(-2y+31)+3=0

We get rid of parentheses

12y+2y-31+3=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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