3(n-5)=3(1-3n)

Solution for 3(n-5)=3(1-3n) equation:

3(n-5)=3(1-3n)

We move all terms to the left:

3(n-5)-(3(1-3n))=0

We add all the numbers together, and all the variables

3(n-5)-(3(-3n+1))=0

We multiply parentheses

3n-(3(-3n+1))-15=0


We calculate terms in parentheses: -(3(-3n+1)), so:

3(-3n+1)

We multiply parentheses

-9n+3

Back to the equation:

-(-9n+3)


We get rid of parentheses

3n+9n-3-15=0

We add all the numbers together, and all the variables

12n-18=0

We move all terms containing n to the left, all other terms to the right

12n=18

n=18/12

n=1+1/2