20+2(t-10)+7=9t+11-7t-4

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Solution for 20+2(t-10)+7=9t+11-7t-4 equation: 



20+2(t-10)+7=9t+11-7t-4

We move all terms to the left:

20+2(t-10)+7-(9t+11-7t-4)=0

We add all the numbers together, and all the variables

2(t-10)-(2t+7)+20+7=0

We add all the numbers together, and all the variables

2(t-10)-(2t+7)+27=0

We multiply parentheses

2t-(2t+7)-20+27=0

We get rid of parentheses

2t-2t-7-20+27=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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