2(y-5)-1=-5(-3y+5)-5y

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Solution for 2(y-5)-1=-5(-3y+5)-5y equation: 



2(y-5)-1=-5(-3y+5)-5y

We move all terms to the left:

2(y-5)-1-(-5(-3y+5)-5y)=0

We multiply parentheses

2y-(-5(-3y+5)-5y)-10-1=0



We calculate terms in parentheses: -(-5(-3y+5)-5y), so:

-5(-3y+5)-5y

We add all the numbers together, and all the variables

-5y-5(-3y+5)

We multiply parentheses

-5y+15y-25

We add all the numbers together, and all the variables

10y-25

Back to the equation:

-(10y-25)



We add all the numbers together, and all the variables

2y-(10y-25)-11=0

We get rid of parentheses

2y-10y+25-11=0

We add all the numbers together, and all the variables

-8y+14=0

We move all terms containing y to the left, all other terms to the right

-8y=-14

y=-14/-8

y=1+3/4

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