3(n-5)-(4-2n)=4n

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Solution for 3(n-5)-(4-2n)=4n equation: 



3(n-5)-(4-2n)=4n

We move all terms to the left:

3(n-5)-(4-2n)-(4n)=0

We add all the numbers together, and all the variables

3(n-5)-(-2n+4)-4n=0

We add all the numbers together, and all the variables

-4n+3(n-5)-(-2n+4)=0

We multiply parentheses

-4n+3n-(-2n+4)-15=0

We get rid of parentheses

-4n+3n+2n-4-15=0

We add all the numbers together, and all the variables

n-19=0

We move all terms containing n to the left, all other terms to the right

n=19

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