3(3x-4)+3=4+7x

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Solution for 3(3x-4)+3=4+7x equation: 



3(3x-4)+3=4+7x

We move all terms to the left:

3(3x-4)+3-(4+7x)=0

We add all the numbers together, and all the variables

3(3x-4)-(7x+4)+3=0

We multiply parentheses

9x-(7x+4)-12+3=0

We get rid of parentheses

9x-7x-4-12+3=0

We add all the numbers together, and all the variables

2x-13=0

We move all terms containing x to the left, all other terms to the right

2x=13

x=13/2

x=6+1/2

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