12+4n=4(1n+3)

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Solution for 12+4n=4(1n+3) equation: 



12+4n=4(1n+3)

We move all terms to the left:

12+4n-(4(1n+3))=0

We add all the numbers together, and all the variables

4n-(4(n+3))+12=0



We calculate terms in parentheses: -(4(n+3)), so:

4(n+3)

We multiply parentheses

4n+12

Back to the equation:

-(4n+12)



We get rid of parentheses

4n-4n-12+12=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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