3(n-2)+5(2-n)=16

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Solution for 3(n-2)+5(2-n)=16 equation: 



3(n-2)+5(2-n)=16

We move all terms to the left:

3(n-2)+5(2-n)-(16)=0

We add all the numbers together, and all the variables

3(n-2)+5(-1n+2)-16=0

We multiply parentheses

3n-5n-6+10-16=0

We add all the numbers together, and all the variables

-2n-12=0

We move all terms containing n to the left, all other terms to the right

-2n=12

n=12/-2

n=-6

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