7(y-4)+2=30

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Solution for 7(y-4)+2=30 equation: 



7(y-4)+2=30

We move all terms to the left:

7(y-4)+2-(30)=0

We add all the numbers together, and all the variables

7(y-4)-28=0

We multiply parentheses

7y-28-28=0

We add all the numbers together, and all the variables

7y-56=0

We move all terms containing y to the left, all other terms to the right

7y=56

y=56/7

y=8

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