(v-4)=-v-(5v+1)

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Solution for (v-4)=-v-(5v+1) equation: 



(v-4)=-v-(5v+1)

We move all terms to the left:

(v-4)-(-v-(5v+1))=0

We get rid of parentheses

v-(-v-(5v+1))-4=0



We calculate terms in parentheses: -(-v-(5v+1)), so:

-v-(5v+1)

We add all the numbers together, and all the variables

-1v-(5v+1)

We get rid of parentheses

-1v-5v-1

We add all the numbers together, and all the variables

-6v-1

Back to the equation:

-(-6v-1)



We get rid of parentheses

v+6v+1-4=0

We add all the numbers together, and all the variables

7v-3=0

We move all terms containing v to the left, all other terms to the right

7v=3

v=3/7

v=3/7

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