3(n-2)+16=7(n-2)

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Solution for 3(n-2)+16=7(n-2) equation: 



3(n-2)+16=7(n-2)

We move all terms to the left:

3(n-2)+16-(7(n-2))=0

We multiply parentheses

3n-(7(n-2))-6+16=0



We calculate terms in parentheses: -(7(n-2)), so:

7(n-2)

We multiply parentheses

7n-14

Back to the equation:

-(7n-14)



We add all the numbers together, and all the variables

3n-(7n-14)+10=0

We get rid of parentheses

3n-7n+14+10=0

We add all the numbers together, and all the variables

-4n+24=0

We move all terms containing n to the left, all other terms to the right

-4n=-24

n=-24/-4

n=+6

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