5(y+1)=3(y+1)+8

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Solution for 5(y+1)=3(y+1)+8 equation: 



5(y+1)=3(y+1)+8

We move all terms to the left:

5(y+1)-(3(y+1)+8)=0

We multiply parentheses

5y-(3(y+1)+8)+5=0



We calculate terms in parentheses: -(3(y+1)+8), so:

3(y+1)+8

We multiply parentheses

3y+3+8

We add all the numbers together, and all the variables

3y+11

Back to the equation:

-(3y+11)



We get rid of parentheses

5y-3y-11+5=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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