3(h+2)+4(h+2)=35

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Solution for 3(h+2)+4(h+2)=35 equation: 



3(h+2)+4(h+2)=35

We move all terms to the left:

3(h+2)+4(h+2)-(35)=0

We multiply parentheses

3h+4h+6+8-35=0

We add all the numbers together, and all the variables

7h-21=0

We move all terms containing h to the left, all other terms to the right

7h=21

h=21/7

h=3

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