3(n+4)=5(n-4)

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Solution for 3(n+4)=5(n-4) equation: 



3(n+4)=5(n-4)

We move all terms to the left:

3(n+4)-(5(n-4))=0

We multiply parentheses

3n-(5(n-4))+12=0



We calculate terms in parentheses: -(5(n-4)), so:

5(n-4)

We multiply parentheses

5n-20

Back to the equation:

-(5n-20)



We get rid of parentheses

3n-5n+20+12=0

We add all the numbers together, and all the variables

-2n+32=0

We move all terms containing n to the left, all other terms to the right

-2n=-32

n=-32/-2

n=+16

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