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(-1/3)d+(3/4)=(5/4)
We move all terms to the left:
(-1/3)d+(3/4)-((5/4))=0
Domain of the equation: 3)d!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
(-1/3)d+(+3/4)-((+5/4))=0
We multiply parentheses
-1d^2+(+3/4)-((+5/4))=0
We get rid of parentheses
-1d^2+3/4-((+5/4))=0
We calculate fractions
-1d^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$d=\frac{-b}{2a}=\frac{0}{-2}=0$
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