3(n+3)=4n+40

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Solution for 3(n+3)=4n+40 equation:



3(n+3)=4n+40
We move all terms to the left:
3(n+3)-(4n+40)=0
We multiply parentheses
3n-(4n+40)+9=0
We get rid of parentheses
3n-4n-40+9=0
We add all the numbers together, and all the variables
-1n-31=0
We move all terms containing n to the left, all other terms to the right
-n=31
n=31/-1
n=-31

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