2(4c+2)=2(3c+8)

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Solution for 2(4c+2)=2(3c+8) equation: 



2(4c+2)=2(3c+8)

We move all terms to the left:

2(4c+2)-(2(3c+8))=0

We multiply parentheses

8c-(2(3c+8))+4=0



We calculate terms in parentheses: -(2(3c+8)), so:

2(3c+8)

We multiply parentheses

6c+16

Back to the equation:

-(6c+16)



We get rid of parentheses

8c-6c-16+4=0

We add all the numbers together, and all the variables

2c-12=0

We move all terms containing c to the left, all other terms to the right

2c=12

c=12/2

c=6

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