-4(4v-3)+2v=2(v+5)

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Solution for -4(4v-3)+2v=2(v+5) equation: 



-4(4v-3)+2v=2(v+5)

We move all terms to the left:

-4(4v-3)+2v-(2(v+5))=0

We add all the numbers together, and all the variables

2v-4(4v-3)-(2(v+5))=0

We multiply parentheses

2v-16v-(2(v+5))+12=0



We calculate terms in parentheses: -(2(v+5)), so:

2(v+5)

We multiply parentheses

2v+10

Back to the equation:

-(2v+10)



We add all the numbers together, and all the variables

-14v-(2v+10)+12=0

We get rid of parentheses

-14v-2v-10+12=0

We add all the numbers together, and all the variables

-16v+2=0

We move all terms containing v to the left, all other terms to the right

-16v=-2

v=-2/-16

v=1/8

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