7(+5x2)=748

Solution for 7(+5x2)=748 equation:

7(+5x^2)=748

We move all terms to the left:

7(+5x^2)-(748)=0

We multiply parentheses

35x^2-748=0

a = 35; b = 0; c = -748;
Δ = b2-4ac
Δ = 02-4·35·(-748)
Δ = 104720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{104720}=\sqrt{16*6545}=\sqrt{16}*\sqrt{6545}=4\sqrt{6545}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6545}}{2*35}=\frac{0-4\sqrt{6545}}{70}
=-\frac{4\sqrt{6545}}{70}
=-\frac{2\sqrt{6545}}{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6545}}{2*35}=\frac{0+4\sqrt{6545}}{70}
=\frac{4\sqrt{6545}}{70}
=\frac{2\sqrt{6545}}{35}
$